2501x^2-900=0

Solution for 2501x^2-900=0 equation:

2501x^2-900=0

a = 2501; b = 0; c = -900;
Δ = b2-4ac
Δ = 02-4·2501·(-900)
Δ = 9003600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{9003600}=\sqrt{3600*2501}=\sqrt{3600}*\sqrt{2501}=60\sqrt{2501}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-60\sqrt{2501}}{2*2501}=\frac{0-60\sqrt{2501}}{5002}
=-\frac{60\sqrt{2501}}{5002}
=-\frac{30\sqrt{2501}}{2501}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+60\sqrt{2501}}{2*2501}=\frac{0+60\sqrt{2501}}{5002}
=\frac{60\sqrt{2501}}{5002}
=\frac{30\sqrt{2501}}{2501}
$